A) \[50cal\]
B) \[70cal\]
C) \[60cal\]
D) \[65cal\]
Correct Answer: A
Solution :
From\[\Delta Q=2{{C}_{p}}(\Delta T)\] \[70=2\times {{C}_{p}}\times (35-30)\] \[{{C}_{p}}=\frac{70}{10}=7cal/mol\,\,{}^\circ C\] \[\Delta Q=m{{C}_{V}}(\Delta T\_=2\times 5\times 5=50\,\,cal\]You need to login to perform this action.
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