A) \[0.763\,\,J\]
B) \[0.345\,\,J\]
C) \[1.5\,\,J\]
D) zero
Correct Answer: A
Solution :
For a thin ring \[KE=\frac{1}{2}I{{\omega }^{2}}\] Here,\[I=m{{r}^{2}}=2.7{{(0.08)}^{2}}=0.0172kg-{{m}^{2}}\] \[\omega =1.5rev/s=3\pi \,\,rad/s\] After substituting the values, we get \[KE=0.763\,\,J\]You need to login to perform this action.
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