A) \[2\,\,mv\]
B) \[\frac{mv}{\sqrt{2}}\]
C) \[mv\sqrt{2}\]
D) zero
Correct Answer: C
Solution :
The horizontal momentum does not change. The change in vertical momentum is \[mv\sin \theta -(-mv\sin \theta )=2mv\frac{1}{\sqrt{2}}\] \[=\sqrt{2}mv\]You need to login to perform this action.
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