A) \[\frac{2v}{a}\]
B) \[\frac{v}{a}\]
C) \[\frac{v}{2a}\]
D) \[\sqrt{\frac{v}{2a}}\]
Correct Answer: A
Solution :
\[{{s}_{A}}=ut+\frac{1}{2}a{{t}^{2}}\] or \[{{s}_{A}}=0+\frac{1}{2}a{{t}^{2}}=\frac{1}{2}a{{t}^{2}}\] \[{{s}_{B}}=vt\] Given, \[{{s}_{A}}={{s}_{B}}\] \[\therefore \] \[\frac{1}{2}a{{t}^{2}}=vt\] or \[t=\frac{2v}{a}\]You need to login to perform this action.
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