A) \[1\times {{10}^{-3}}N\]
B) \[2\times {{10}^{-3}}N\]
C) \[4\times {{10}^{-3}}N\]
D) \[0.25\times {{10}^{-3}}N\]
Correct Answer: C
Solution :
Force between two parallel current carrying wires on their unit length \[F=\frac{{{\mu }_{0}}}{4\pi }\frac{{{i}_{1}}{{i}_{2}}}{r}\] Hence, \[F\propto {{i}_{1}}{{i}_{2}}\] or \[\frac{{{F}_{1}}}{{{F}_{2}}}=\frac{{{i}_{1}}{{i}_{2}}}{2{{i}_{1}}\cdot 2{{i}_{2}}}\] or \[\frac{1\times {{10}^{-3}}}{{{F}_{2}}}=\frac{10\times 10}{2\times 10\times 2\times 10}\] or \[{{F}_{2}}=4\times {{10}^{-3}}N\]
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