A ray of light is incident at polarising angle such that its deviation is \[{{24}^{o}}\], then angle of incidence is
A)\[{{24}^{o}}\]
B)\[{{57}^{o}}\]
C)\[{{66}^{o}}\]
D)\[{{90}^{o}}\]
Correct Answer:
B
Solution :
Here\[{{i}_{p}}=r+\delta \] \[{{i}_{p}}=r+24\] ... (i) Moreover \[{{i}_{p}}+r={{90}^{o}}\] ... (ii) From Eqs. (i) and (ii), we get \[{{i}_{p}}({{i}_{p}}-{{24}^{o}})={{90}^{o}}\] \[{{i}_{p}}={{57}^{o}}\]