A) \[163\,\,kJ\,\,mo{{l}^{-1}}\]
B) \[2.4\times {{10}^{2}}\,\,kJ\,\,mo{{l}^{-1}}\]
C) \[1.63\,\,kJ\,\,mo{{l}^{-1}}\]
D) \[2.38\times {{10}^{6}}\,\,kJ\,\,mo{{l}^{-1}}\]
Correct Answer: A
Solution :
\[\Delta {{G}^{o}}=-2.303Rt\log {{K}_{p}}\] \[\Delta {{G}^{o}}=-2.303\times (8.314)\times (298)\] \[(\log 2.47\times {{10}^{-29}})\] \[\Delta {{G}^{o}}=163000\,\,J\,\,mo{{l}^{-1}}\] \[=163\,\,kJ\,\,mo{{l}^{-1}}\]You need to login to perform this action.
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