A) acetamide
B) propionamide
C) form amide
D) methylcyanide
Correct Answer: B
Solution :
Reaction of an amide with bromine and caustic potash results in the degradation of carbon chain by one carbon atom i. e., the \[-CON{{H}_{2}}\]group is transformed into\[-N{{H}_{2}}\]group. Therefore, to prepare ethyl amine (an amine with two carbon atoms), an amide with three carbon atoms\[(C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}})\]will have to be used. Thus, \[\underset{\text{propionamide}}{\mathop{C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}}}}\,\xrightarrow{B{{r}_{2}}/KOH}\underset{\text{ethyl}\,\,\text{amine}}{\mathop{C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}}}\,\]
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