A) molecular weight
B) \[\frac{molecular\text{ }weight}{3}\]
C) \[\frac{molecular\text{ }weight}{6}\]
D) \[\frac{molecular\text{ }weight}{2}\]
Correct Answer: C
Solution :
\[2Cr{{(OH)}_{3}}+4O{{H}^{-}}+\overset{+5}{\mathop{KI{{O}_{3}}}}\,\xrightarrow[{}]{{}}2CrO_{4}^{2-}\] \[+5{{H}_{2}}\text{O}+\overset{-1}{\mathop{KI}}\,\] In\[KI{{O}_{3}}\]change in the oxidation number of effective element\[(I)=+5-(-1)\] \[=6\] Equivalent weight of oxidising agent \[=\frac{molecular\text{ }weight}{change\text{ }in\text{ }oxidation\text{ }number\text{ }per\text{ }molecule}\] Equivalent weight of \[KI{{O}_{3}}=\frac{molecular\text{ }weight}{6}\]You need to login to perform this action.
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