A) \[F{{e}^{2+}}\]ion
B) \[{{K}_{3}}[Fe{{(CN)}_{6}}]\]
C) \[C{{N}^{-}}\]ion
D) None of these
Correct Answer: B
Solution :
\[\underset{\begin{smallmatrix} potassium \\ ferrocyanide \end{smallmatrix}}{\mathop{2{{K}_{4}}[Fe{{(CN)}_{6}}+{{O}_{3}}}}\,\xrightarrow[{}]{{{H}_{2}}O}\] \[\underset{\begin{smallmatrix} potassium \\ femcyanide \end{smallmatrix}}{\mathop{2{{K}_{3}}[Fe{{(CN)}_{6}}+2KOH}}\,+{{O}_{2}}]\]You need to login to perform this action.
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