A) \[Li>Na>K>Rb>Cs\]
B) \[Cs>Rb>K>Na>Li\]
C) \[Cs>Rb>K>Li>Na\]
D) \[Cs>K>Rb>Na>Li\]
Correct Answer: A
Solution :
Decreasing order of radius of hydrated ions of \[Li,Na,K,Rb\] and Cs is:Hydrated ion | \[Li_{(aq)}^{+}\] | \[>Na_{(aq)}^{+}\] | \[>K_{(aq)}^{+}\] | \[>Rb_{(aq)}^{+}\] | \[>Cs_{(aq)}^{+}\] |
Radius (in \[\overset{o}{\mathop{\text{A}}}\,\]) | 3.40 | 2.76 | 2.32 | 2.28 | 2.27 |
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