A) 8 V
B) 4 V
C) 2 V
D) 6 V
Correct Answer: A
Solution :
Equivalent capacity of combination \[\frac{1}{C}=\frac{1}{4.5}+\frac{1}{(6+3)}\] \[\Rightarrow \] \[C=3\mu F\] Therefore charge on capacitance of capacity \[4.5\mu F\] \[q=3\times 12=36C\] \[\therefore \]Potential difference on capacitance of capacity \[4.5\mu F\] \[V=\frac{q}{C}\] \[=\frac{36}{4.5}=8V\]You need to login to perform this action.
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