When \[{{H}_{2}}\]reacts with\[C{{l}_{2}}\] in presence of sunlight to form \[HCl\]then order of reaction will be (unit of\[K=mol\,{{L}^{-1}}{{S}^{-1}}\])
A) 2
B) 3
C) 0
D) 4
Correct Answer:
C
Solution :
\[{{H}_{2}}+C{{l}_{2}}\xrightarrow[{}]{hv}2HCl\] This is zero order reaction.