A) 3, 2, 6
B) 2, 3, 1
C) 1, 2, 3
D) 1, 1, 1
Correct Answer: A
Solution :
Miller's indices is calculated as: \[h=\frac{a}{2a}=\frac{1}{2}\] \[k=\frac{b}{3b}=\frac{1}{3}\] \[l=\frac{c}{c}=1\] \[h:k:l=\frac{1}{2}:\frac{1}{3}:\frac{1}{1}\] \[=3:2:6\] Hence, Miller's indices is 3, 2, 6.You need to login to perform this action.
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