A) 4/13
B) 1/169
C) 2/13
D) None of these
Correct Answer: B
Solution :
Probability of getting first ace from the pack\[=\frac{4}{52}\] Probability that second card is also ace\[=\frac{4}{52}\] \[\therefore \]Probability that both the cards are ace \[=\frac{4}{52}.\frac{4}{52}\] \[=\frac{1}{13}.\frac{1}{13}=\frac{1}{169}\]You need to login to perform this action.
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