A) 6
B) 3
C) 4
D) 12
Correct Answer: D
Solution :
Period of\[\sin \frac{\pi x}{2}=\frac{2\pi }{\pi /2}=4\] Period of\[\cos \frac{\pi x}{3}=\frac{2\pi }{\pi /3}=6\] and period of\[\tan \frac{\pi x}{4}=\frac{\pi }{\pi /4}=4\] \[\therefore \]Period of the given function \[f(x)\] = LCM of 4, 6 and 4 \[=12\]You need to login to perform this action.
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