A) 1 : 2
B) 1 : 1
C) 3 : 1
D) 2 : 1
Correct Answer: D
Solution :
\[E=kl,\]if emf of cells are\[{{E}_{1}}\]and \[{{E}_{2}}\] then \[{{E}_{1}}+{{E}_{2}}=k\times 6\] ...(i) and \[{{E}_{1}}-{{E}_{2}}=k\times 2\] ...(ii) From Eqs. (i) and (ii), we have \[\Rightarrow \] \[\frac{{{E}_{1}}+{{E}_{2}}}{{{E}_{1}}-{{E}_{2}}}=\frac{3}{1}\] \[\Rightarrow \] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{2}{1}\]You need to login to perform this action.
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