A) \[2{{V}_{e}}\]
B) \[3{{V}_{e}}\]
C) \[4{{V}_{e}}\]
D) None of these
Correct Answer: A
Solution :
Escape velocity at surface of earth, \[{{v}_{e}}=\sqrt{2gR}\] \[\Rightarrow \] \[{{v}_{e}}\propto \sqrt{gR}\] Suppose escape velocity at planet is\[{{v}_{e}}',\]then \[\frac{{{v}_{e}}'}{{{v}_{e}}}=\sqrt{\frac{g'}{g}.\frac{R'}{R}}=\sqrt{2\times 2}=2\] \[\Rightarrow \] \[{{v}_{e}}'=2{{v}_{e}}\]
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