RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    AB is a wire of uniform resistance. The galvanometer G shows no current when the length AB=20 cm and BC =80 cm. The resistance  R is equal to

    A)  20\[\Omega \]

    B)  80\[\Omega \]                 

    C)  10\[\Omega \]         

    D)  40\[\Omega \]

    Correct Answer: A

    Solution :

     For\[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{{{L}_{1}}}{{{L}_{2}}}\] \[\Rightarrow \] \[{{R}_{1}}=\frac{{{L}_{1}}}{{{L}_{2}}}\times {{R}_{2}}=\frac{20}{80}\times 80=20\,\Omega \]


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