A) double
B) half
C) one-fourth
D) four times
Correct Answer: D
Solution :
\[E\propto T\] \[\Rightarrow \] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{27+273}{927+273}=\frac{300}{1200}=\frac{1}{4}\] \[\Rightarrow \] \[{{E}_{2}}=4{{E}_{1}}\]You need to login to perform this action.
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