A) F
B) 2F
C) F/2
D) zero
Correct Answer: A
Solution :
\[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{(7)(-5)\times {{10}^{-12}}}{{{r}^{2}}}N\] Again \[F'=\frac{1}{4\pi {{\varepsilon }_{0}}}\] \[=\frac{(7-2)(-5-2)\times {{10}^{-12}}}{{{r}^{2}}}N\] \[F'=F\]You need to login to perform this action.
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