A) from 6 to 3
B) from -6 to 3
C) from + 3 to 0
D) from + 6 to 0
Correct Answer: A
Solution :
\[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\xrightarrow[{}]{reduction}C{{r}^{3+}}\] Oxidation number of Cr changes from +6 to +3.You need to login to perform this action.
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