A) 1
B) 2
C) 0
D) None of these
Correct Answer: C
Solution :
a, b, c, d, e are in AP. \[\therefore \] \[2b=a+c,2c=b+d,2d=c+e,\] \[a-4b+6c-4d+e\] \[=a-4b+6c-2c-2e+e\] \[=a-4b+4c-e\] \[=a-4b+2b+2d-e\] \[=a-2b+2d-e\] \[=a-a-c+c+e-e\] \[=0\]You need to login to perform this action.
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