A) 1
B) \[-1\]
C) \[\sin x\]
D) \[\cos x\]
Correct Answer: B
Solution :
\[y={{\tan }^{-1}}\left( \frac{1-\tan x}{1+\tan x} \right)={{\tan }^{-1}}\tan \left( \frac{\pi }{4}-x \right)\] \[\therefore \] \[y=\frac{\pi }{4}-x\] \[\Rightarrow \] \[\frac{dy}{dx}=-1\]You need to login to perform this action.
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