A) 0.4 A
B) \[-0.4\text{ }A\]
C) 0.8 A
D) \[-0.08\text{ }A\]
Correct Answer: B
Solution :
At junction A, \[{{I}_{3}}={{I}_{1}}+{{I}_{2}}\] ?.(i) In loop ABCDA, from the Kirchhoffs Voltage Law \[-30{{I}_{1}}-40{{I}_{3}}+40=0\] \[-30{{I}_{1}}-40({{I}_{1}}+{{I}_{2}})+40=0\] \[7{{I}_{1}}+4{{I}_{2}}=4\] ...(ii) In loop ADEFA, from the Kirchhoffs Voltage Law \[-40{{I}_{2}}-40({{I}_{1}}-{{I}_{2}})=-120\] \[{{I}_{1}}+{{I}_{2}}=3\] ...(iii) From Eqs. (i) and (ii), we get \[{{I}_{1}}=-0.4A\]You need to login to perform this action.
You will be redirected in
3 sec