A) \[\frac{3}{2}k\]
B) \[\frac{2}{3}k\]
C) \[2k\]
D) \[3k\]
Correct Answer: B
Solution :
Springs (2) and (3) are in parallel. Therefore, its equivalent force constant will be 2k. Again 2k and spring (1) are in series. Therefore, equivalent force constant \[\frac{1}{K'}=\frac{1}{k}+\frac{1}{2k}=\frac{3}{2k}\] \[K'=\frac{2}{3}k\]You need to login to perform this action.
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