A) \[{{10}^{42}}\]
B) 10
C) 1
D) \[{{10}^{-43}}\]
Correct Answer: D
Solution :
\[\frac{{{F}_{g}}}{{{F}_{e}}}=\frac{G\frac{m.m}{{{r}^{2}}}}{\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}}=\frac{6.67\times {{10}^{-11}}\times (9.1\times {{10}^{-31}})}{9\times {{10}^{9}}\times {{(1.6\times {{10}^{-19}})}^{2}}}\] \[\approx {{10}^{-43}}\]You need to login to perform this action.
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