A) ionization potential of Na is greater than K
B) size of Na is smaller than K
C) atomic weight of K is greater than Na
D) only eight electrons are present in third shell of K
Correct Answer: D
Solution :
\[Na(11)=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{1}}\] \[K(19)=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}},4{{s}^{1}}\] The density of Na is higher than K because only eight electrons, are present in the third shell of K, hence the size of K increases abnormally.
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