A) 2 : 1
B) 1 : 4
C) 1 : 8
D) 8 : 1
Correct Answer: C
Solution :
\[Y=\frac{FL}{\pi {{r}^{2}}.\,l}\] \[\Rightarrow \] \[\frac{{{L}_{1}}}{r_{1}^{2}.{{l}_{1}}}=\frac{{{L}^{2}}}{r_{2}^{2}{{l}_{2}}}\] \[\Rightarrow \] \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{{{L}_{1}}}{{{L}_{2}}}\times \frac{r_{2}^{2}}{r_{1}^{2}}=\left( \frac{1}{2} \right)\times {{\left( \frac{1}{2} \right)}^{2}}\] \[\Rightarrow \] \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{1}{8}\]You need to login to perform this action.
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