A) barbituric acid
B) semicarbazide
C) methylol urea
D) acetamide
Correct Answer: B
Solution :
\[\underset{urea}{\mathop{N{{H}_{2}}CON{{H}_{2}}}}\,+N{{H}_{3}}\to \underset{semicarbazide}{\mathop{{{H}_{2}}NCONH.N{{H}_{2}}}}\,+{{H}_{2}}\]
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