A) \[1-\alpha \]
B) \[1+\alpha \]
C) \[1-2\alpha \]
D) \[1+2\alpha \]
Correct Answer: D
Solution :
\[A\xrightarrow[{}]{{}}2B+C\]1 | 0 | 0 | at initial |
\[1-\alpha \] | \[2\alpha \] | \[\alpha \] | at equilibrium |
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