A) 2
B) \[-2\]
C) 1
D) \[-1\]
Correct Answer: B
Solution :
Equation of polar to the circle\[{{x}^{2}}+{{y}^{2}}=3\]at the point\[(3,\lambda )\] \[3x+\lambda y=3\] ...(i) Since, the points\[(3,\lambda )\]and (5, 6) are conjugate with respect to the circle. \[\therefore \] (5, 6) will satisfy the Eq. (i) \[\therefore \] \[3\times 5+\lambda \times 6=3\] \[\Rightarrow \] \[6\lambda =3-15\] \[\Rightarrow \] \[\lambda =-\frac{12}{6}\] \[\Rightarrow \] \[\lambda =-2\]You need to login to perform this action.
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