A) Primary alcohol
B) Secondary alcohol
C) Tertiary alcohol
D) Ketone
Correct Answer: B
Solution :
\[\underset{acetaldehyde}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{C}}\,=O}}\,+\underset{\begin{smallmatrix} Grignard's \\ reagent \end{smallmatrix}}{\mathop{C{{H}_{3}}MgBr}}\,\xrightarrow[{}]{{}}\] \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-OMgBr\xrightarrow[{}]{{{H}_{2}}O}\underset{secondary\text{ }alcohol}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-OH}}\,\]
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