A) 1
B) 0
C) \[\omega \]
D) \[{{\omega }^{2}}+1\]
Correct Answer: B
Solution :
\[\left| \begin{matrix} 1 & \omega & {{\omega }^{2}} \\ \omega & {{\omega }^{2}} & 1 \\ {{\omega }^{2}} & 1 & \omega \\ \end{matrix} \right|=\left| \begin{matrix} 1+\omega +{{\omega }^{2}} & \omega & {{\omega }^{2}} \\ \omega +{{\omega }^{2}}+1 & {{\omega }^{2}} & 1 \\ {{\omega }^{2}}+1+\omega & 1 & \omega \\ \end{matrix} \right|\] \[[{{C}_{1}}\to {{C}_{1}}+{{C}_{2}}+{{C}_{3}}]\] \[=\left| \begin{matrix} 0 & \omega & {{\omega }^{2}} \\ 0 & {{\omega }^{2}} & 1 \\ 0 & 1 & \omega \\ \end{matrix} \right|\]\[[\because 1+\omega +{{\omega }^{2}}=0]\] \[=0\]
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