A) 1
B) 2
C) 0
D) \[-1\]
Correct Answer: C
Solution :
If the points (1,2),\[(-1,x)\] and (2, 3) are collinear, then area of the triangle made by these points is zero. i.e., \[\left| \begin{matrix} 1 & 2 & 1 \\ -1 & x & 1 \\ 2 & 3 & 1 \\ \end{matrix} \right|=0\] \[\Rightarrow \] \[1(x-3)-2(-1-2)+1(-3-2x)=0\] \[\Rightarrow \] \[x-3+6-3-2x=0\] \[\Rightarrow \] \[-x=0\] \[\Rightarrow \] \[x=0\]You need to login to perform this action.
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