A) \[\frac{1}{f(x)}\]
B) \[\frac{1}{f(y)}\]
C) \[yf(x)\]
D) \[f(y)\]
Correct Answer: D
Solution :
\[\because \]\[y=f(x)=\frac{ax+b}{cx-a}\] \[\Rightarrow \] \[y(cx-a)=ax+b\] \[\Rightarrow \] \[(yc-a)x=b+ay\] \[\Rightarrow \] \[x=\frac{ay+b}{cy-a}=f(y)\]You need to login to perform this action.
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