A) \[f(\theta )+f(\phi )\]
B) \[f(\theta -\phi )\]
C) \[f\left( \frac{\theta }{\phi } \right)\]
D) \[\theta -\phi \]
Correct Answer: B
Solution :
Given,\[f(\theta )=\tan \theta ,\]then \[f(\phi )=\tan \phi \] \[\therefore \] \[\frac{f(\theta )-f(\phi )}{1+f(\theta )f(\phi )}=\frac{\tan \theta -\tan \phi }{1+\tan \theta \tan \phi }\] \[=\tan (\theta -\phi )\] \[=f(\theta -\phi )\]You need to login to perform this action.
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