A) 0
B) \[-1\]
C) \[-2\]
D) \[-3\]
Correct Answer: C
Solution :
Let\[\overrightarrow{a}=2\hat{i}+\hat{j}-\hat{k}\]and\[\overrightarrow{b}=\hat{i}-4\hat{j}+\lambda \hat{k}\] Since,\[\overrightarrow{a}\]and\[\overrightarrow{b}\]are perpendicular each other \[\therefore \] \[\overrightarrow{a}.\overrightarrow{b}=0\] \[\Rightarrow \] \[(2\hat{i}+\hat{j}-\hat{k}).(\hat{i}-4\hat{j}+\lambda \hat{k})=0\] \[\Rightarrow \] \[2-4-\lambda =0\] \[\Rightarrow \] \[-\lambda -2=0\] \[\Rightarrow \] \[\lambda =-2\]You need to login to perform this action.
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