A) 5 cm, 2s
B) 5 cm, \[\frac{1}{2}\]s
C) 5 cm, 4s
D) 5 cm, \[\frac{1}{4}\]s
Correct Answer: A
Solution :
\[y=5\sin (\pi t+4\pi )\] The amplitude of wave = 5 cm The time period of wave \[=\frac{2\pi }{\omega }=\frac{2\pi }{\pi }\] \[=2s\]You need to login to perform this action.
You will be redirected in
3 sec