A) \[2\times {{10}^{-3}}m\]
B) \[2.5\times {{10}^{-3}}m\]
C) \[2\times {{10}^{-4}}\]
D) \[4\times {{10}^{-3}}m\]
Correct Answer: A
Solution :
\[F=2\pi rT\] \[\Rightarrow \] \[r=\frac{F}{2\pi T}\] \[=\frac{6.28\times {{10}^{-4}}}{2\times 3.14\times 5\times {{10}^{-2}}}=2\times {{10}^{-3}}m\]You need to login to perform this action.
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