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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2003

  • question_answer
    In a potentiometer experiment two cells of emf? s \[{{E}_{1}}\]and\[{{E}_{2}}\]are used in series and in conjunction and the balancing length is found to be 58 cm of the wire. If the polarity of\[{{E}_{2}}\]is reversed, then the balancing length becomes 29 cm. The ratio \[\frac{{{E}_{1}}}{{{E}_{2}}}\]of the emf of the two cells is

    A)  1 : 1             

    B)  2 : 1

    C)  3 : 1             

    D)  4 : 1

    Correct Answer: C

    Solution :

     \[({{E}_{1}}+{{E}_{2}})=x\times 58\]                       ...(i) where\[x=\]potential gradient and      \[({{E}_{1}}-{{E}_{2}})=x\times 29\]                 ...(ii) \[\frac{{{E}_{1}}+{{E}_{2}}}{{{E}_{1}}-{{E}_{2}}}=\frac{58}{29}=\frac{2}{1}\] \[\frac{{{E}_{1}}}{{{E}_{2}}}=3\]


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