A) \[\frac{6.62\,\times \,{{10}^{-19}}}{4\pi }\]
B) \[6.62\,\times \,{{10}^{-29}}\]
C) \[6.62\,\times \,{{10}^{-39}}\]
D) \[6.62\,\times \,{{10}^{-49}}\]
Correct Answer: A
Solution :
\[\Delta p\times \Delta x\ge \frac{h}{4\pi }\] \[\Delta p\ge \frac{h}{4\pi \,\Delta x}=\frac{6.62\times {{10}^{-34}}}{4\pi \times {{10}^{-15}}}\] \[=\frac{6.62\times {{10}^{-19}}}{4\pi }\]
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