A) 1 : 1
B) 2 : 1
C) 3 : 1
D) 4 : 1
Correct Answer: C
Solution :
\[({{E}_{1}}+{{E}_{2}})=x\times 58\] ...(i) where\[x=\]potential gradient and \[({{E}_{1}}-{{E}_{2}})=x\times 29\] ...(ii) \[\frac{{{E}_{1}}+{{E}_{2}}}{{{E}_{1}}-{{E}_{2}}}=\frac{58}{29}=\frac{2}{1}\] \[\frac{{{E}_{1}}}{{{E}_{2}}}=3\]You need to login to perform this action.
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