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  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2003

  • question_answer
    The energy needed to remove the one electron from neutral helium atom is 24.6 eV. Then the energy needed to remove both the electrons from neutral helium atom is             

    A)  79.0 eV          

    B)  51.8 eV

    C)  49.2 eV          

    D)  38.2 eV

    Correct Answer: A

    Solution :

     \[E=13.6\times \frac{{{(Z)}^{2}}}{1}=54.4eV\] Total energy \[=24.6+54.4=79\text{ }eV\]


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