A) \[\frac{cv}{c-v}\]
B) \[\frac{cv}{c-2v}\]
C) \[\frac{2vv}{c}\]
D) \[\frac{2cv}{v}\]
Correct Answer: C
Solution :
\[v'=v\left( \frac{c+v}{2} \right)\] \[=v\frac{v}{c}\] \[\therefore \]indicator is completely change \[\Delta v=\frac{2{{v}_{e}}}{c}\]
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