A) \[(-3,\text{ }8)\]
B) (2, 3)
C) (3, 2)
D) None of these
Correct Answer: A
Solution :
Equation of line perpendicular to\[2x-y-1=0\]is \[x+2y+\lambda =0\] It passes through the point (3, 5) \[\therefore \] \[3+2\times 5+\lambda =0\] \[\Rightarrow \] \[\lambda =-13\] \[\therefore \] Equation is\[x+2y=13\] ...(i) Centre of circle lies on the line\[x+y=5\]...(ii) On solving Eqs. (i) and (ii), we get \[x=-3,y=8\] Hence, coordinates of centre of circle is\[(-3,8)\]You need to login to perform this action.
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