A) \[\pi /3\]
B) \[\pi /6\]
C) \[\pi /2\]
D) \[\pi \]
Correct Answer: A
Solution :
\[x=a\sin \left( \omega t+\frac{\pi }{6} \right)\] \[x'=a\sin \left( \omega t+\frac{\pi }{2} \right)\] Phase difference\[={{\phi }_{2}}-{{\phi }_{1}}\] \[=\frac{\pi }{2}-\frac{\pi }{6}=\frac{\pi }{3}\]You need to login to perform this action.
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