question_answer

\[C{{H}_{3}}MgX+A\xrightarrow[{}]{{}}B\xrightarrow[{}]{{{H}_{3}}{{O}^{\oplus }}}C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH\] Compound A, in the above reaction is

A)  \[C{{H}_{3}}C{{H}_{2}}CHO\]    

B)  \[C{{H}_{3}}CHO\]

C)  \[{{(C{{H}_{2}})}_{2}}O\]        

D)  \[{{(C{{H}_{3}})}_{2}}CO\]

Correct Answer: C

Solution :

  \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-OMgX\xrightarrow[{}]{{{H}_{3}}{{O}^{+}}}\underset{propanol-1}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH}}\,\]