A) 8
B) 4
C) 6
D) 1
Correct Answer: B
Solution :
\[n'=n\left( \frac{v-{{v}_{0}}}{v} \right)\] \[n''=n\left( \frac{v+{{v}_{0}}}{v} \right)\] \[\Delta n=n''-n'=\frac{2n{{v}_{0}}}{v}\] \[=\frac{2\times 330\times 2}{330}\] \[=4\]You need to login to perform this action.
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