A) \[1-\alpha \]
B) \[1+\alpha \]
C) \[1-2\alpha \]
D) \[1+2\alpha \]
Correct Answer: D
Solution :
\[A2B+C\]1 | 0 | 0 | in initial |
\[1-\alpha \] | \[2\alpha \] | \[\alpha \] | at eqm. |
You need to login to perform this action.
You will be redirected in
3 sec